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0=2x^2+20x-44
We move all terms to the left:
0-(2x^2+20x-44)=0
We add all the numbers together, and all the variables
-(2x^2+20x-44)=0
We get rid of parentheses
-2x^2-20x+44=0
a = -2; b = -20; c = +44;
Δ = b2-4ac
Δ = -202-4·(-2)·44
Δ = 752
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{752}=\sqrt{16*47}=\sqrt{16}*\sqrt{47}=4\sqrt{47}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{47}}{2*-2}=\frac{20-4\sqrt{47}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{47}}{2*-2}=\frac{20+4\sqrt{47}}{-4} $
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